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physics-angular acceleration?
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 2.0 cm and accelerates at the rate of 6.6 rad/s^2, and it is in contact with the pottery wheel (radius 25.0 cm) without slipping.
(a) Calculate the angular acceleration of the pottery wheel.
(b) Calculate the time it takes the pottery wheel to reach its required speed of 70 rpm.
Thanks. that was very helpful. the only thing is that you made a slight error while computing the answer for a.) is .53, and therefore the answer for b.) is 13.87. But not a problem! thanks for showing the work and for the help!
(a)since both are in touch without slipping, thus their linear acceleration will be same
=>a = r1 x alfa1 = r2 x alfa2
=>alfa2 = 2 x 6.6/25 = 0.59 rad/sec^2
(b) 70 rpm = 70/60 = 1.17 revolution/sec = n
=>omega = 2 x pi x n = 2 x 3.14 x 1.17 = 7.35 rad/sec
By omega2 = omega1 + alfa x t
=>7.35 = 0 + 0.59 x t
=>t = 12.46 sec